# Solving Concentration Problems

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2) Concentration by Mole: We can express concentration of solutions by moles. It is denoted with "m" and formula of molality is; 4) Normality: We can express concentration in another way with normality using equivalents of solutes.

Number of moles per liter is called molarity shown with M. If we add water to solution, moles of solute decreases. n=16/40=0,4 mole V=200 m L= 0,2 Liters Molarity=0,4/0,2=2 molar I is true II. If we add water to solution, volume of solution increases but moles of solute does not change.

If concentration of solution is 20 %, we understand that there are 20 g solute in 100 g solution.

Example: 10 g salt and 70 g water are mixed and solution is prepared. Solution: Mass of Solute: 10 g Mass of Solution: 10 70 = 80 g 80 g solution includes 10 g solute 100 g solution includes X g solute ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ X=12,5 g % Or using formula; Percent by mass=10.100/80=12,5 % Example: If concentration by mass of 600 g Na Cl solution is 40 %, find amount of solute by mass in this solution.

Molarity is one of the most common and important units of concentration used in chemistry.

This concentration problem illustrates how to find the molarity of a solution if you know how much solute and solvent are present.

In a lab setting, you may be asked to find the molarity, or molar concentration, of the solution instead.

Tip: You don’t need to include the volume of the solute since it doesn’t usually affect the volume that much.

We can express concentration in different ways like concentration by percent or by moles.

1) Concentration by Percent: It is the amount of solute dissolves in 100 g solvent.

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